Contoh
soal dan jawaban “MOMEN INERSIA “
*yukkk belajar fisika!
![](file:///C:/Users/User/AppData/Local/Temp/msohtmlclip1/01/clip_image001.png)
![](file:///C:/Users/User/AppData/Local/Temp/msohtmlclip1/01/clip_image002.png)
![](file:///C:/Users/User/AppData/Local/Temp/msohtmlclip1/01/clip_image003.png)
![](file:///C:/Users/User/AppData/Local/Temp/msohtmlclip1/01/clip_image004.png)
![](file:///C:/Users/User/AppData/Local/Temp/msohtmlclip1/01/clip_image005.png)
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2m 3m 4m
Hitung
momen inersia sistem diatas!
Jawaban
:
I
= m1R12+m2R22+m3R32
= 2.52+3.32+4.42
= 50+27+64
= 141 kg m2
2.
Massa bumi adalah 5,97 x 1024 kg dan jari-jari bumi rata-rata adalah
6731 km.Hitung momen inersia bumi!
Jawaban
:
I = mR2
= 25.97 x 1024 . 67310002
![](file:///C:/Users/User/AppData/Local/Temp/msohtmlclip1/01/clip_image007.png)
= 0,4 . 270 . 51 x 1036
= 108.20 x 1036 kgm2
Created By : Student SMK 2 GARUT
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